(2x+3)(x^2+x-5)=

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Solution for (2x+3)(x^2+x-5)= equation: 


Simplifying
(2x + 3)(x2 + x + -5) = 0

Reorder the terms:
(3 + 2x)(x2 + x + -5) = 0

Reorder the terms:
(3 + 2x)(-5 + x + x2) = 0

Multiply (3 + 2x) * (-5 + x + x2)
(3(-5 + x + x2) + 2x * (-5 + x + x2)) = 0
((-5 * 3 + x * 3 + x2 * 3) + 2x * (-5 + x + x2)) = 0
((-15 + 3x + 3x2) + 2x * (-5 + x + x2)) = 0
(-15 + 3x + 3x2 + (-5 * 2x + x * 2x + x2 * 2x)) = 0
(-15 + 3x + 3x2 + (-10x + 2x2 + 2x3)) = 0

Reorder the terms:
(-15 + 3x + -10x + 3x2 + 2x2 + 2x3) = 0

Combine like terms: 3x + -10x = -7x
(-15 + -7x + 3x2 + 2x2 + 2x3) = 0

Combine like terms: 3x2 + 2x2 = 5x2
(-15 + -7x + 5x2 + 2x3) = 0

Solving
-15 + -7x + 5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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